The Senator paid for 40 wins

I guess I rarely pay attention to salary amounts, but last night I looked through the Bucks payroll on HoopsHype. Wow! I'm glad I'm not the Bucks owner. They have a $71 million payroll! That is nearly equal to the payroll of the Milwaukee Brewers ($79 million) and up their with the Green Bay Packers ($89 million)!! Yet the Brewers employ 20 players at the Major League level ($3.9 million per), and the Packers employ 53 ($1.6 million per)!

So the Bucks, with only 15 players on their payroll (and that includes that bastard Damon Jones, whom the NBA collective bargaining agreement requires the Bucks to pay +$4 million to debate Skip Bayless on ESPN) have in fact the highest payroll of the state's professional teams. And yet the Bucks are, sadly... but clearly... the third most popular professional team in Wisconsin. And I'm not talking third with a bullet either... if you counted the Badgers they might be fourth. The NBA has a screwed up financial model.

But the point of this post is the amount of wins the Senator deserves in return. Well, if you take the total amount of salary paid by the NBA's franchises this season and divide it by the number of available wins, you get the market value of a win: $1.77 million. Thus, Senator Kohl has paid for 40 wins.

But if he gets them, they won't come according to outlay. The two highest paid players -- Michael Redd and Richard Jefferson -- owe the Senator 8.9 and 7.4 wins respectively. Redd is currently on pace to